Needed for a titration lab:
1. Buret
2. Stopcock
3. Pipet (Glass tube)
4. Erlenmeyer Flask
5. Indicators- Used to identify the end point of filtration
6. Stock solution - Known Solution
Mike the explorer completed a titration of 0.330 M NaOH with 15.00 mL samples of HI of unknown concentration. The data he gathered is below. Determine the concentration of HI.
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Subtract the final reading from the initial reading to get the Volume used.
Next we add up 11.2 mL + 10.9 mL + 11.4 mL = divide by 3 = 11.16666667 mL
Doing this gets us the average, but notice how we don't count the volume that was far off.
Next we change 11.16 mL into L
11.16 x 1L/1000 mL
= .0111L
Then, we take our concentration and change that into Moles of HI
0.330 M x .011 L = .00363 x 1 = 0.00363 mol
L 1
Finally, we take 0.00363 mol
and divide it by the 15.00 mL, but remember to convert into L!!
15.00 mL x 1 L/1000 mL
= .015 L
0.00363 mol/ 0.015 L
= .246 M
5. Indicators- Used to identify the end point of filtration
6. Stock solution - Known Solution
Mike the explorer completed a titration of 0.330 M NaOH with 15.00 mL samples of HI of unknown concentration. The data he gathered is below. Determine the concentration of HI.

Subtract the final reading from the initial reading to get the Volume used.
Next we add up 11.2 mL + 10.9 mL + 11.4 mL = divide by 3 = 11.16666667 mL
Doing this gets us the average, but notice how we don't count the volume that was far off.
Next we change 11.16 mL into L
11.16 x 1L/1000 mL
= .0111L
Then, we take our concentration and change that into Moles of HI
0.330 M x .011 L = .00363 x 1 = 0.00363 mol
L 1
Finally, we take 0.00363 mol
and divide it by the 15.00 mL, but remember to convert into L!!
15.00 mL x 1 L/1000 mL
= .015 L
0.00363 mol/ 0.015 L
= .246 M
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